c# - Konvertieren Sie Ganzzahlen in geschriebene Zahlen

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Gibt es eine effiziente Methode zum Konvertieren einer Ganzzahl in die geschriebenen Zahlen, zum Beispiel:

string Written = IntegerToWritten(21);

würde "Twenty One" zurückgeben.

Gibt es eine Möglichkeit, die keine massive Nachschlagetabelle beinhaltet?

This question and all comments follow the "Attribution Required."

Alle Antworten

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Dies sollte einigermaßen gut funktionieren:

public static class HumanFriendlyInteger
{
    static string[] ones = new string[] { "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" };
    static string[] teens = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
    static string[] tens = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
    static string[] thousandsGroups = { "", " Thousand", " Million", " Billion" };

    private static string FriendlyInteger(int n, string leftDigits, int thousands)
    {
        if (n == 0)
        {
            return leftDigits;
        }

        string friendlyInt = leftDigits;

        if (friendlyInt.Length > 0)
        {
            friendlyInt += " ";
        }

        if (n < 10)
        {
            friendlyInt += ones[n];
        }
        else if (n < 20)
        {
            friendlyInt += teens[n - 10];
        }
        else if (n < 100)
        {
            friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
        }
        else if (n < 1000)
        {
            friendlyInt += FriendlyInteger(n % 100, (ones[n / 100] + " Hundred"), 0);
        }
        else
        {
            friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands+1), 0);
            if (n % 1000 == 0)
            {
                return friendlyInt;
            }
        }

        return friendlyInt + thousandsGroups[thousands];
    }

    public static string IntegerToWritten(int n)
    {
        if (n == 0)
        {
            return "Zero";
        }
        else if (n < 0)
        {
            return "Negative " + IntegerToWritten(-n);
        }

        return FriendlyInteger(n, "", 0);
    }
}

(Bearbeitet, um einen Fehler mit Millionen, Milliarden usw. zu beheben.)

Quelle
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Ich benutze diese handliche Bibliothek namens Humanizer.

https://github.com/Humanizr/Humanizer

Es unterstützt mehrere Kulturen und konvertiert nicht nur Zahlen in Wörter, sondern auch Datumsangaben und ist sehr einfach zu bedienen.

So benutze ich es:

int someNumber = 543;
var culture = System.Globalization.CultureInfo("en-US");
var result = someNumber.ToWords(culture); // 543 -> five hundred forty-three

Und voilá!

Quelle
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Ich verwende diesen Code. Es ist VB-Code, aber Sie können ihn leicht in C # übersetzen. Es klappt

Function NumberToText(ByVal n As Integer) As String

   Select Case n
Case 0
  Return ""

Case 1 To 19
  Dim arr() As String = {"One","Two","Three","Four","Five","Six","Seven", _
    "Eight","Nine","Ten","Eleven","Twelve","Thirteen","Fourteen", _
      "Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"}
  Return arr(n-1) & " "

Case 20 to 99
  Dim arr() as String = {"Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"}
  Return arr(n\10 -2) & " " & NumberToText(n Mod 10)

Case 100 to 199
  Return "One Hundred " & NumberToText(n Mod 100)

Case 200 to 999
  Return NumberToText(n\100) & "Hundreds " & NumberToText(n mod 100)

Case 1000 to 1999
  Return "One Thousand " & NumberToText(n Mod 1000)

Case 2000 to 999999
  Return NumberToText(n\1000) & "Thousands " & NumberToText(n Mod 1000)

Case 1000000 to 1999999
  Return "One Million " & NumberToText(n Mod 1000000)

Case 1000000 to 999999999
  Return NumberToText(n\1000000) & "Millions " & NumberToText(n Mod 1000000)

Case 1000000000 to 1999999999
  Return "One Billion " & NumberTotext(n Mod 1000000000)

Case Else
  Return NumberToText(n\1000000000) & "Billion " _
    & NumberToText(n mod 1000000000)
End Select
End Function

Hier ist der Code in c #

public static string AmountInWords(double amount)
{
        var n = (int)amount;

        if (n == 0)
            return "";
        else if (n > 0 && n <= 19)
        {
            var arr = new string[] { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
            return arr[n - 1] + " ";
        }
        else if (n >= 20 && n <= 99)
        {
            var arr = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
            return arr[n / 10 - 2] + " " + AmountInWords(n % 10);
        }
        else if (n >= 100 && n <= 199)
        {
            return "One Hundred " + AmountInWords(n % 100);
        }
        else if (n >= 200 && n <= 999)
        {
            return AmountInWords(n / 100) + "Hundred " + AmountInWords(n % 100);
        }
        else if (n >= 1000 && n <= 1999)
        {
            return "One Thousand " + AmountInWords(n % 1000);
        }
        else if (n >= 2000 && n <= 999999)
        {
            return AmountInWords(n / 1000) + "Thousand " + AmountInWords(n % 1000);
        }
        else if (n >= 1000000 && n <= 1999999)
        {
            return "One Million " + AmountInWords(n % 1000000);
        }
        else if (n >= 1000000 && n <= 999999999)
        {
            return AmountInWords(n / 1000000) + "Million " + AmountInWords(n % 1000000);
        }
        else if (n >= 1000000000 && n <= 1999999999)
        {
            return "One Billion " + AmountInWords(n % 1000000000);
        }
        else
        {
            return AmountInWords(n / 1000000000) + "Billion " + AmountInWords(n % 1000000000);
        }
    }
Quelle
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Justin Rogers hat eine "NumbersToEnglish" -Klasse, die den Job für Sie gut machen sollte!

Erstbuchung.
http://weblogs.asp.net/justin_rogers/archive/2004/06/09/151675.aspx

Finalisierter Quellcode
http://weblogs.asp.net/justin_rogers/articles/151757.aspx

Es hat zwar eine Art interne Nachschlagetabelle, aber ich weiß nicht wirklich, wie Sie davon wegkommen können.

Quelle
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warum massive Nachschlagetabelle?

string GetWrittenInteger(int n)
{
  string[] a = new string[] {"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" }
  string[] b = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" }
  string[] c = new string[] {"Twenty", "Thirty", "Forty", "Sixty", "Seventy", "Eighty", "Ninety"};
  string[] d = new string[] {"Hundred", "Thousand", "Million"}
  string s = n.ToString();

  for (int i = 0; i < s.Length; i++)
  {
    // logic (too lazy but you get the idea)
  }
}
Quelle
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using System;
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 

namespace tryingstartfror4digits 
{ 
    class Program 
    { 
        static void Main(string[] args)
        {
            Program pg = new Program();
            Console.WriteLine("Enter ur number");
            int num = Convert.ToInt32(Console.ReadLine());

            if (num <= 19)
            {
                string g = pg.first(num);
                Console.WriteLine("The number is " + g);
            }
            else if ((num >= 20) && (num <= 99))
            {
                    if (num % 10 == 0)
                    {
                        string g = pg.second(num / 10);
                        Console.WriteLine("The number is " + g);
                    }
                    else
                    {
                        string g = pg.second(num / 10) + pg.first(num % 10);
                        Console.WriteLine("The number is " + g);
                    }
            }
            else if ((num >= 100) && (num <= 999))
            {
                int k = num % 100;
                string g = pg.first(num / 100) +pg.third(0) + pg.second(k / 10)+pg.first(k%10);
                Console.WriteLine("The number is " + g);
            }
            else if ((num >= 1000) && (num <= 19999))
            {
                int h = num % 1000;
                int k = h % 100;
                string g = pg.first(num / 1000) + "Thousand " + pg.first(h/ 100) + pg.third(k) + pg.second(k / 10) + pg.first(k % 10);
                Console.WriteLine("The number is " + g);
            }

            Console.ReadLine();
        }

        public string first(int num)
        {
            string name;

            if (num == 0)
            {
                name = " ";
            }
            else
            {
                string[] arr1 = new string[] { "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" , "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
                name = arr1[num - 1];
            }

            return name;
        }

        public string second(int num)
        {
            string name;

            if ((num == 0)||(num==1))
            {
                 name = " ";
            }
            else
            {
                string[] arr1 = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
                name = arr1[num - 2];
            }

            return name;
        }

        public string third(int num)
        {
            string name ;

            if (num == 0)
            {
                name = "";
            }
            else
            {
                string[] arr1 = new string[] { "Hundred" };
                name = arr1[0];
            }

            return name;
        }
    }
}

Dies funktioniert einwandfrei von 1 bis 19999 wird bald nach Abschluss aktualisiert

Quelle
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Die akzeptierte Antwort scheint nicht perfekt zu funktionieren. Es behandelt keine Bindestriche in Zahlen wie einundzwanzig, es setzt nicht das Wort "und" in Zahlen wie "einhundertein" und es ist rekursiv.

Hier ist mein Schuss auf die Antwort. Es fügt das Wort "und" intelligent hinzu und trennt Zahlen entsprechend. Lassen Sie mich wissen, wenn Änderungen erforderlich sind.

So nennt man es (offensichtlich möchten Sie dies irgendwo in eine Klasse einordnen):

for (int i = int.MinValue+1; i < int.MaxValue; i++)
{
    Console.WriteLine(ToWords(i));
}

Hier ist der Code:

private static readonly string[] Ones = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"};

private static readonly string[] Teens =
{
    "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen",
    "Seventeen", "Eighteen", "Nineteen"
};

private static readonly string[] Tens =
{
    "", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty",
    "Ninety"
};

public static string ToWords(int number)
{
    if (number == 0)
        return "Zero";

    var wordsList = new List<string>();

    if (number < 0)
    {
        wordsList.Add("Negative");
        number = Math.Abs(number);
    }

    if (number >= 1000000000 && number <= int.MaxValue) //billions
    {
        int billionsValue = number / 1000000000;
        GetValuesUnder1000(billionsValue, wordsList);
        wordsList.Add("Billion");
        number -= billionsValue * 1000000000;

        if (number > 0 && number < 10)
            wordsList.Add("and");
    }

    if (number >= 1000000 && number < 1000000000) //millions
    {
        int millionsValue = number / 1000000;
        GetValuesUnder1000(millionsValue, wordsList);
        wordsList.Add("Million");
        number -= millionsValue * 1000000;

        if (number > 0 && number < 10)
            wordsList.Add("and");
    }

    if (number >= 1000 && number < 1000000) //thousands
    {
        int thousandsValue = number/1000;
        GetValuesUnder1000(thousandsValue, wordsList);
        wordsList.Add("Thousand");
        number -= thousandsValue * 1000;

        if (number > 0 && number < 10)
            wordsList.Add("and");
    }

    GetValuesUnder1000(number, wordsList);

    return string.Join(" ", wordsList);
}

private static void GetValuesUnder1000(int number, List<string> wordsList)
{
    while (number != 0)
    {
        if (number < 10)
        {
            wordsList.Add(Ones[number]);
            number -= number;
        }
        else if (number < 20)
        {
            wordsList.Add(Teens[number - 10]);
            number -= number;
        }
        else if (number < 100)
        {
            int tensValue = ((int) (number/10))*10;
            int onesValue = number - tensValue;

            if (onesValue == 0)
            {
                wordsList.Add(Tens[tensValue/10]);
            }
            else
            {
                wordsList.Add(Tens[tensValue/10] + "-" + Ones[onesValue]);
            }

            number -= tensValue;
            number -= onesValue;
        }
        else if (number < 1000)
        {
            int hundredsValue = ((int) (number/100))*100;
            wordsList.Add(Ones[hundredsValue/100]);
            wordsList.Add("Hundred");
            number -= hundredsValue;

            if (number > 0)
                wordsList.Add("and");
        }
    }
}
Quelle
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Hier ist einC # -Konsolenanwendungdas gibt ganze Zahlen sowie Dezimalstellen zurück.

Quelle
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Eine Erweiterung von Nick Masaos Antwort für Bengali Numeric des gleichen Problems. Die anfängliche Eingabe der Zahl erfolgt in einer Unicode-Zeichenfolge. Prost!!

string number = "২২৮৯";
number = number.Replace("০", "0").Replace("১", "1").Replace("২", "2").Replace("৩", "3").Replace("৪", "4").Replace("৫", "5").Replace("৬", "6").Replace("৭", "7").Replace("৮", "8").Replace("৯", "9");
double vtempdbl = Convert.ToDouble(number);
string amount = AmountInWords(vtempdbl);

private static string AmountInWords(double amount)
    {
        var n = (int)amount;

        if (n == 0)
            return " ";
        else if (n > 0 && n <= 99)
        {
            var arr = new string[] {  "এক", "দুই",  "তিন",  "চার",  "পাঁচ", "ছয়",  "সাত",  "আট",   "নয়",  "দশ",   "এগার", "বারো", "তের",  "চৌদ্দ",    "পনের", "ষোল", "সতের", "আঠার", "ঊনিশ", "বিশ",  "একুশ", "বাইস", "তেইশ", "চব্বিশ",   "পঁচিশ",    "ছাব্বিশ",  "সাতাশ",    "আঠাশ", "ঊনত্রিশ",  "ত্রিশ",    "একত্রিস",  "বত্রিশ",   "তেত্রিশ",  "চৌত্রিশ",  "পঁয়ত্রিশ", "ছত্রিশ",   "সাঁইত্রিশ",    "আটত্রিশ",  "ঊনচল্লিশ", "চল্লিশ",   "একচল্লিশ", "বিয়াল্লিশ",    "তেতাল্লিশ",    "চুয়াল্লিশ",    "পয়তাল্লিশ",    "ছিচল্লিশ", "সাতচল্লিশ",    "আতচল্লিশ", "উনপঞ্চাশ", "পঞ্চাশ",   "একান্ন",   "বায়ান্ন",  "তিপ্পান্ন",    "চুয়ান্ন",  "পঞ্চান্ন", "ছাপ্পান্ন",    "সাতান্ন",  "আটান্ন",   "উনষাট",    "ষাট",  "একষট্টি",  "বাষট্টি",  "তেষট্টি",  "চৌষট্টি",  "পয়ষট্টি",  "ছিষট্টি",  " সাতষট্টি",    "আটষট্টি",  "ঊনসত্তর ", "সত্তর",    "একাত্তর ", "বাহাত্তর", "তেহাত্তর", "চুয়াত্তর", "পঁচাত্তর", "ছিয়াত্তর", "সাতাত্তর", "আটাত্তর",  "ঊনাশি",    "আশি",  "একাশি",    "বিরাশি",   "তিরাশি",   "চুরাশি",   "পঁচাশি",   "ছিয়াশি",   "সাতাশি",   "আটাশি",    "উননব্বই",  "নব্বই",    "একানব্বই", "বিরানব্বই",    "তিরানব্বই",    "চুরানব্বই",    "পঁচানব্বই ",   "ছিয়ানব্বই ",   "সাতানব্বই",    "আটানব্বই", "নিরানব্বই" };
            return arr[n - 1] + " ";
        }
        else if (n >= 100 && n <= 199)
        {
            return AmountInWords(n / 100) + "এক শত " + AmountInWords(n % 100);
        }

        else if (n >= 100 && n <= 999)
        {
            return AmountInWords(n / 100) + "শত " + AmountInWords(n % 100);
        }
        else if (n >= 1000 && n <= 1999)
        {
            return "এক হাজার " + AmountInWords(n % 1000);
        }
        else if (n >= 1000 && n <= 99999)
        {
            return AmountInWords(n / 1000) + "হাজার " + AmountInWords(n % 1000);
        }
        else if (n >= 100000 && n <= 199999)
        {
            return "এক লাখ " + AmountInWords(n % 100000);
        }
        else if (n >= 100000 && n <= 9999999)
        {
            return AmountInWords(n / 100000) + "লাখ " + AmountInWords(n % 100000);
        }
        else if (n >= 10000000 && n <= 19999999)
        {
            return "এক কোটি " + AmountInWords(n % 10000000);
        }
        else
        {
            return AmountInWords(n / 10000000) + "কোটি " + AmountInWords(n % 10000000);
        }
    }
Quelle
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Der folgende C # -Konsolen-App-Code akzeptiert einen Geldwert in Zahlen bis zu 2 Dezimalstellen und druckt ihn in Englisch aus. Dies wandelt nicht nur die Ganzzahl in das englische Äquivalent um, sondern auch als Geldwert in Dollar und Cent.

 namespace ConsoleApplication2
{
    using System;
    using System.Collections.Generic;
    using System.Linq;
    using System.Text.RegularExpressions;
    class Program
    {
       static void Main(string[] args)
        {
            bool repeat = true;
            while (repeat)
            {
                string inputMonetaryValueInNumberic = string.Empty;
                string centPart = string.Empty;
                string dollarPart = string.Empty;
                Console.Write("\nEnter the monetary value : ");
                inputMonetaryValueInNumberic = Console.ReadLine();
                inputMonetaryValueInNumberic = inputMonetaryValueInNumberic.TrimStart('0');

                if (ValidateInput(inputMonetaryValueInNumberic))
                {

                    if (inputMonetaryValueInNumberic.Contains('.'))
                    {
                        centPart = ProcessCents(inputMonetaryValueInNumberic.Substring(inputMonetaryValueInNumberic.IndexOf(".") + 1));
                        dollarPart = ProcessDollar(inputMonetaryValueInNumberic.Substring(0, inputMonetaryValueInNumberic.IndexOf(".")));
                    }
                    else
                    {
                        dollarPart = ProcessDollar(inputMonetaryValueInNumberic);
                    }
                    centPart = string.IsNullOrWhiteSpace(centPart) ? string.Empty : " and " + centPart;
                    Console.WriteLine(string.Format("\n\n{0}{1}", dollarPart, centPart));
                }
                else
                {
                    Console.WriteLine("Invalid Input..");
                }

                Console.WriteLine("\n\nPress any key to continue or Escape of close : ");
                var loop = Console.ReadKey();
                repeat = !loop.Key.ToString().Contains("Escape");
                Console.Clear();
            }

        }

        private static string ProcessCents(string cents)
        {
            string english = string.Empty;
            string dig3 = Process3Digit(cents);
            if (!string.IsNullOrWhiteSpace(dig3))
            {
                dig3 = string.Format("{0} {1}", dig3, GetSections(0));
            }
            english = dig3 + english;
            return english;
        }
        private static string ProcessDollar(string dollar)
        {
            string english = string.Empty;
            foreach (var item in Get3DigitList(dollar))
            {
                string dig3 = Process3Digit(item.Value);
                if (!string.IsNullOrWhiteSpace(dig3))
                {
                    dig3 = string.Format("{0} {1}", dig3, GetSections(item.Key));
                }
                english = dig3 + english;
            }
            return english;
        }
        private static string Process3Digit(string digit3)
        {
            string result = string.Empty;
            if (Convert.ToInt32(digit3) != 0)
            {
                int place = 0;
                Stack<string> monetaryValue = new Stack<string>();
                for (int i = digit3.Length - 1; i >= 0; i--)
                {
                    place += 1;
                    string stringValue = string.Empty;
                    switch (place)
                    {
                        case 1:
                            stringValue = GetOnes(digit3[i].ToString());
                            break;
                        case 2:
                            int tens = Convert.ToInt32(digit3[i]);
                            if (tens == 1)
                            {
                                if (monetaryValue.Count > 0)
                                {
                                    monetaryValue.Pop();
                                }
                                stringValue = GetTens((digit3[i].ToString() + digit3[i + 1].ToString()));
                            }
                            else
                            {
                                stringValue = GetTens(digit3[i].ToString());
                            }
                            break;
                        case 3:
                            stringValue = GetOnes(digit3[i].ToString());
                            if (!string.IsNullOrWhiteSpace(stringValue))
                            {
                                string postFixWith = " Hundred";
                                if (monetaryValue.Count > 0)
                                {
                                    postFixWith = postFixWith + " And";
                                }
                                stringValue += postFixWith;
                            }
                            break;
                    }
                    if (!string.IsNullOrWhiteSpace(stringValue))
                        monetaryValue.Push(stringValue);
                }
                while (monetaryValue.Count > 0)
                {
                    result += " " + monetaryValue.Pop().ToString().Trim();
                }
            }
            return result;
        }
        private static Dictionary<int, string> Get3DigitList(string monetaryValueInNumberic)
        {
            Dictionary<int, string> hundredsStack = new Dictionary<int, string>();
            int counter = 0;
            while (monetaryValueInNumberic.Length >= 3)
            {
                string digit3 = monetaryValueInNumberic.Substring(monetaryValueInNumberic.Length - 3, 3);
                monetaryValueInNumberic = monetaryValueInNumberic.Substring(0, monetaryValueInNumberic.Length - 3);
                hundredsStack.Add(++counter, digit3);
            }
            if (monetaryValueInNumberic.Length != 0)
                hundredsStack.Add(++counter, monetaryValueInNumberic);
            return hundredsStack;
        }
        private static string GetTens(string tensPlaceValue)
        {
            string englishEquvalent = string.Empty;
            int value = Convert.ToInt32(tensPlaceValue);
            Dictionary<int, string> tens = new Dictionary<int, string>();
            tens.Add(2, "Twenty");
            tens.Add(3, "Thirty");
            tens.Add(4, "Forty");
            tens.Add(5, "Fifty");
            tens.Add(6, "Sixty");
            tens.Add(7, "Seventy");
            tens.Add(8, "Eighty");
            tens.Add(9, "Ninty");
            tens.Add(10, "Ten");
            tens.Add(11, "Eleven");
            tens.Add(12, "Twelve");
            tens.Add(13, "Thrteen");
            tens.Add(14, "Fourteen");
            tens.Add(15, "Fifteen");
            tens.Add(16, "Sixteen");
            tens.Add(17, "Seventeen");
            tens.Add(18, "Eighteen");
            tens.Add(19, "Ninteen");
            if (tens.ContainsKey(value))
            {
                englishEquvalent = tens[value];
            }

            return englishEquvalent;

        }
        private static string GetOnes(string onesPlaceValue)
        {
            int value = Convert.ToInt32(onesPlaceValue);
            string englishEquvalent = string.Empty;
            Dictionary<int, string> ones = new Dictionary<int, string>();
            ones.Add(1, " One");
            ones.Add(2, " Two");
            ones.Add(3, " Three");
            ones.Add(4, " Four");
            ones.Add(5, " Five");
            ones.Add(6, " Six");
            ones.Add(7, " Seven");
            ones.Add(8, " Eight");
            ones.Add(9, " Nine");

            if (ones.ContainsKey(value))
            {
                englishEquvalent = ones[value];
            }

            return englishEquvalent;
        }
        private static string GetSections(int section)
        {
            string sectionName = string.Empty;
            switch (section)
            {
                case 0:
                    sectionName = "Cents";
                    break;
                case 1:
                    sectionName = "Dollars";
                    break;
                case 2:
                    sectionName = "Thousand";
                    break;
                case 3:
                    sectionName = "Million";
                    break;
                case 4:
                    sectionName = "Billion";
                    break;
                case 5:
                    sectionName = "Trillion";
                    break;
                case 6:
                    sectionName = "Zillion";
                    break;
            }
            return sectionName;
        }
        private static bool ValidateInput(string input)
        {
            return Regex.IsMatch(input, "[0-9]{1,18}(\\.[0-9]{1,2})?"))
        }
    }
}
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Holen Sie sich einfach diesen String und konvertieren Sie ihn mit dem gleichen Wert als String s = txtNumber.Text.Tostring (); int i = Convert.ToInt32 (s.Tostring ()); Es wird nur der vollständige ganzzahlige Wert geschrieben

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Nur zur türkischen Vertretung der KlasseHumanFriendlyInteger(↑) (Türkçe, sayı yazı karşılığı):

public static class HumanFriendlyInteger
{
    static string[] ones = new string[] { "", "Bir", "İki", "Üç", "Dört", "Beş", "Altı", "Yedi", "Sekiz", "Dokuz" };
    static string[] teens = new string[] { "On", "On Bir", "On İki", "On Üç", "On Dört", "On Beş", "On Altı", "On Yedi", "On Sekiz", "On Dokuz" };
    static string[] tens = new string[] { "Yirmi", "Otuz", "Kırk", "Elli", "Altmış", "Yetmiş", "Seksen", "Doksan" };
    static string[] thousandsGroups = { "", " Bin", " Milyon", " Milyar" };

    private static string FriendlyInteger(int n, string leftDigits, int thousands)
    {
        if (n == 0)
        {
            return leftDigits;
        }

        string friendlyInt = leftDigits;

        if (friendlyInt.Length > 0)
        {
            friendlyInt += " ";
        }

        if (n < 10)
            friendlyInt += ones[n];
        else if (n < 20)
            friendlyInt += teens[n - 10];
        else if (n < 100)
            friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
        else if (n < 1000)
            friendlyInt += FriendlyInteger(n % 100, ((n / 100 == 1 ? "" : ones[n / 100] + " ") + "Yüz"), 0); // Yüz 1 ile başlangıçta "Bir" kelimesini Türkçe'de almaz.
        else
            friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands + 1), 0);

        return friendlyInt + thousandsGroups[thousands];
    }

    public static string IntegerToWritten(int n)
    {
        if (n == 0)
            return "Sıfır";
        else if (n < 0)
            return "Eksi " + IntegerToWritten(-n);

        return FriendlyInteger(n, "", 0);
    }
Quelle